I would say one good reason is that
waitlock myapp &
JOB_PID=$!
# ... do exclusive work ...
kill $JOB_PID
(; flock -n 9 || exit 1; # ... commands executed under lock ...; ) 9>/var/lock/mylockfile (; flock -n 9
( flock -n 9
?`for ((i = 0 ; i < max ; i++ )); do echo "$i"; done`
Here this is essentially a "while" loop, meaning it will keep executing the commands as long as we don't reach `exit 1`.
(; flock -n 9 || exit 1; # ... commands executed under lock ...; )
[~] 0 $ ( flock -n 9 || exit 1; echo in loop ; sleep 3 ; echo done working ; ) 9>~/tmp/mylock
in loop
done working
[~] 0 $ (; flock -n 9 || exit 1; echo in loop ; sleep 3 ; echo done working ; ) 9>~/tmp/mylock
-bash: syntax error near unexpected token `;'
[~] 2 $
Flock -s file && script.
Pretty simple. (I forgot the argument, I think is -s..
waitlock myapp & #... do stuff waitlock --done myapp
asddfgg55•6mo ago
eddythompson80•6mo ago
bigattichouse•6mo ago