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The only U.S. particle collider shuts down

https://www.sciencenews.org/article/particle-collider-shuts-down-brookhaven
1•rolph•55s ago•0 comments

Ask HN: Why do purchased B2B email lists still have such poor deliverability?

1•solarisos•1m ago•0 comments

Show HN: Remotion directory (videos and prompts)

https://www.remotion.directory/
1•rokbenko•3m ago•0 comments

Portable C Compiler

https://en.wikipedia.org/wiki/Portable_C_Compiler
1•guerrilla•5m ago•0 comments

Show HN: Kokki – A "Dual-Core" System Prompt to Reduce LLM Hallucinations

1•Ginsabo•5m ago•0 comments

Software Engineering Transformation 2026

https://mfranc.com/blog/ai-2026/
1•michal-franc•7m ago•0 comments

Microsoft purges Win11 printer drivers, devices on borrowed time

https://www.tomshardware.com/peripherals/printers/microsoft-stops-distrubitng-legacy-v3-and-v4-pr...
2•rolph•7m ago•0 comments

Lunch with the FT: Tarek Mansour

https://www.ft.com/content/a4cebf4c-c26c-48bb-82c8-5701d8256282
2•hhs•10m ago•0 comments

Old Mexico and her lost provinces (1883)

https://www.gutenberg.org/cache/epub/77881/pg77881-images.html
1•petethomas•14m ago•0 comments

'AI' is a dick move, redux

https://www.baldurbjarnason.com/notes/2026/note-on-debating-llm-fans/
2•cratermoon•15m ago•0 comments

The source code was the moat. But not anymore

https://philipotoole.com/the-source-code-was-the-moat-no-longer/
1•otoolep•15m ago•0 comments

Does anyone else feel like their inbox has become their job?

1•cfata•15m ago•0 comments

An AI model that can read and diagnose a brain MRI in seconds

https://www.michiganmedicine.org/health-lab/ai-model-can-read-and-diagnose-brain-mri-seconds
2•hhs•18m ago•0 comments

Dev with 5 of experience switched to Rails, what should I be careful about?

1•vampiregrey•21m ago•0 comments

AlphaFace: High Fidelity and Real-Time Face Swapper Robust to Facial Pose

https://arxiv.org/abs/2601.16429
1•PaulHoule•22m ago•0 comments

Scientists discover “levitating” time crystals that you can hold in your hand

https://www.nyu.edu/about/news-publications/news/2026/february/scientists-discover--levitating--t...
2•hhs•24m ago•0 comments

Rammstein – Deutschland (C64 Cover, Real SID, 8-bit – 2019) [video]

https://www.youtube.com/watch?v=3VReIuv1GFo
1•erickhill•24m ago•0 comments

Tell HN: Yet Another Round of Zendesk Spam

2•Philpax•24m ago•0 comments

Postgres Message Queue (PGMQ)

https://github.com/pgmq/pgmq
1•Lwrless•28m ago•0 comments

Show HN: Django-rclone: Database and media backups for Django, powered by rclone

https://github.com/kjnez/django-rclone
1•cui•31m ago•1 comments

NY lawmakers proposed statewide data center moratorium

https://www.niagara-gazette.com/news/local_news/ny-lawmakers-proposed-statewide-data-center-morat...
1•geox•32m ago•0 comments

OpenClaw AI chatbots are running amok – these scientists are listening in

https://www.nature.com/articles/d41586-026-00370-w
3•EA-3167•33m ago•0 comments

Show HN: AI agent forgets user preferences every session. This fixes it

https://www.pref0.com/
6•fliellerjulian•35m ago•0 comments

Introduce the Vouch/Denouncement Contribution Model

https://github.com/ghostty-org/ghostty/pull/10559
2•DustinEchoes•37m ago•0 comments

Show HN: SSHcode – Always-On Claude Code/OpenCode over Tailscale and Hetzner

https://github.com/sultanvaliyev/sshcode
1•sultanvaliyev•37m ago•0 comments

Microsoft appointed a quality czar. He has no direct reports and no budget

https://jpcaparas.medium.com/microsoft-appointed-a-quality-czar-he-has-no-direct-reports-and-no-b...
2•RickJWagner•39m ago•0 comments

Multi-agent coordination on Claude Code: 8 production pain points and patterns

https://gist.github.com/sigalovskinick/6cc1cef061f76b7edd198e0ebc863397
1•nikolasi•39m ago•0 comments

Washington Post CEO Will Lewis Steps Down After Stormy Tenure

https://www.nytimes.com/2026/02/07/technology/washington-post-will-lewis.html
13•jbegley•40m ago•3 comments

DevXT – Building the Future with AI That Acts

https://devxt.com
2•superpecmuscles•41m ago•4 comments

A Minimal OpenClaw Built with the OpenCode SDK

https://github.com/CefBoud/MonClaw
1•cefboud•41m ago•0 comments
Open in hackernews

When 1+1+1 Equals 1

https://mathenchant.wordpress.com/2024/12/19/when-111-equals-1/
41•surprisetalk•2mo ago

Comments

pyuser583•2mo ago
Interesting. I always associate "1 + 1 = 1" with idempotency. Here, "1 + 1 + 1 = 1", but "1 + 1 = 0".

I'm not a math whiz, so I'm just stuck with "1 + 1 = 2."

aatd86•2mo ago
you're wrong. 1 + 1 = 10
lisper•2mo ago
Which of course is 0 mod 2.
aatd86•2mo ago
And 0^0 x 2
not_a_bot_4sho•2mo ago
My son once asked me what 1+1 was equal to. I said, "two!"

He said, "no, it's eleven." And that's when I realized he's going to be a JavaScript coder.

harperlee•2mo ago
XOR is a simple operation that shows that behavior.
khannn•2mo ago
Terrence Howard has entered the chat
kevin_thibedeau•2mo ago
Shhh! Don't give them any ideas.
susam•2mo ago
A simple example where 1 + 1 + 1 = 1 is ℤ₂, the group of integers modulo 2 under addition.

In fact, in any group with binary operation, say +, the identity element 0, and a non-identity element a, we have a + a + a = a if and only if a + a = 0 (i.e. a has order 2).

There are plenty of groups with elements a satisfying a + a = 0. ℤ₂ as mentioned above has its unique non-zero element of order 2. The Klein group V₄ has three non-identity elements, each of order 2. Dihedral groups D₂ₙ (the symmetry groups of regular n-gons) contain reflections, all of which have order 2. Symmetric groups Sₙ (n ≥ 2) contain transpositions, each of which has order 2.

For example, in the dihedral group D₈, if we let a be a reflection of the square, then a + a = 0 and a + a + a = a. But this is conventionally written in multiplicative notation as a² = the identity element, so a³ = a.

Similarly, in the symmetric group S₃ under the binary operation of composition, if a denotes the transposition (12), then (12)(12) is the identity element and (12)(12)(12) = (12). In other words, applying a transposition three times is the same as applying it once.

In the last two examples, it is conventional to use product notation instead of +, although whether we use + or · for the binary operation does not matter mathematically. It is conventional to use + in some subjects (coding theory, additive groups of integers modulo n, etc.) and · in others (permutation groups, dihedral groups, etc.). Often + is used for the binary operation in abelian groups and · in non-abelian ones. I'm sure none of this is particularly insightful to someone who has studied group theory, but still I wanted to share a few concrete examples here.

HWR_14•2mo ago
[My post below is wrong]

> In fact, in any group with binary operation +, identity element 0, and a non-identity element a, we have a + a + a = a if and only if a + a = 0 (i.e. a has order 2).

The "if" is correct. The "only if" is not. (I assume that '+' and '0' are used as shorthand for "any binary operation" and "the identity of that binary operation", as I don't recall cases where "+" and "*" are used for specific types of binary operations).

susam•2mo ago
> The "if" is correct. The "only if" is not.

Both "if" and "only if" are correct.

Let a + a + a = a. Adding the inverse of a to both sides, we get a + a = 0.

Let a + a = 0. Adding a to both sides, we get a + a + a = a.

> I assume that '+' and '0' are used as shorthand for "any binary operation" and "the identity of that binary operation"

Yes. As I mentioned in my previous comment, "In the last two examples, it is conventional to use product notation instead of +, although whether we use + or · for the binary operation does not matter mathematically."

In multiplicative notation, the statement becomes: a·a·a = a holds if and only if a·a = e, where e denotes the identity element.

HWR_14•2mo ago
> mentioned this in my previous comment

You did. I'm sorry I glossed over the ending to your comment. I was focused on a counterexample I was working on and went only on my memory of group theory.

> Adding the additive inverse of a, i.e., -a from both sides, we get a + a = 0.

That assumes associativity, but that's a nitpick, not a real objection.

In reality, I got a bit tired and mentally shifted the question to a + a + a = 0, not a + a + a = a. That of course has numerous examples. But is irrelevant.

Thanks for taking the time for the thoughtful, and non-snarky, response. Sorry if I was abrupt before.

susam•2mo ago
> That assumes associativity, but that's a nitpick, not a real objection.

I don't think that is a valid nitpick. My earlier comments assume associativity because a group operation is associative by definition. If we do not allow associativity, then the algebraic structure we are working with is no longer a group at all. It would just be a loop (which is a quasigroup which in turn is magma).

> Thanks for taking the time for the thoughtful, and non-snarky, response. Sorry if I was abrupt before.

No worries at all. I'm glad to have a place on the Internet where I can talk about these things now and then. Thank you for engaging in the discussion.

HWR_14•2mo ago
You are again right. I misrecalled a group as a loop.

Thank you again. It's been too long since I've had to use this knowledge and am happy to have the opportunity to (try to) use it.

patrickthebold•2mo ago
I'd be good to give an example of where the 'only if' doesn't apply. If only to clear up the confusion.
HWR_14•2mo ago
Sorry, I had a mental skip. I was thinking of solutions to a+a+a=0, not a+a+a=a.
thaumasiotes•2mo ago
> The Klein group V₄ has three non-identity elements, each of order 2.

Unrelated, but this calls out for a link to the classic song Finite Simple Group (of Order Two) by the Klein Four: https://www.youtube.com/watch?v=BipvGD-LCjU

vbsd•2mo ago
> A simple example where 1 + 1 + 1 = 1 is ℤ₂, the group of integers modulo 2 under addition.

That’s a good example of an algebra where 1 + 1 + 1 = 1, but the article is specifically about systems where in addition to that condition, this second condition is also true: 1 + 1 != 0 (not equal!). ℤ₂ is not an example of that.

kazinator•2mo ago
1 + 1 + 1 ≡ 1 (modulo 2)

In the modulo 2 congruence, 1 + 1 + 1 is the same element as 1.

discoinverno•2mo ago
The piece is about something else, cases when 1 + 1 + 1 ≡ 1 but 1 + 1 != 0
voxleone•2mo ago
Beautiful math tricks. For things like these I think math education should start with sets and groups instead of numbers.

https://d1gesto.blogspot.com/2025/11/math-education-what-if-...

cbm-vic-20•2mo ago
I like Chapter 1 of Evan Chen's An Infinitely Large Napkin for some more theory.

https://web.evanchen.cc/napkin.html

CyberDildonics•2mo ago
I'm not a mathematician but I don't think that's right.
anthk•2mo ago
1 as a boolean? true
moxons-master•2mo ago
In tropical geometry, tropical multiplication (⊙) is replaced by standard addition (+), and tropical addition (⊕) is replaced by the minimum (min) function, so 1⊕1⊕1=min{1,1,1}=1.
SilasX•2mo ago
>there are other operations that aren’t quite involutions – “near-involutions”, one might call them2 – that nonetheless have the property that thrice is the same as once, four times is the same as twice, etc. ... Unlike mod-two arithmetic, which is about counting “zero, one, zero, one, zero, one, …,” the kind of counting that governs these operations goes “zero, one, two, one two, one two, …”

Interesting! Earlier I had a shower thought about "what would be an variant of idempotence?" That's where an operation has the same effect whether done one or many times.

One variant would be "has the same effect whether one two or many times". Another would be "can be in any one of two possible states after done one or many times" (as opposed to one possible state for idempotence). This looks like the latter!

ttz•2mo ago
modulo 2
solomonb•2mo ago
The intuitionistic negation example is so mind blowing. I can only wrap my head around it when I think about it in terms of functions and types:

    not : Type -> Type
    not P = P -> ⊥
    
    modus-ponens : P -> ((f : P -> Q) -> Q)
    modus-ponens p = λf. f p
    
    -- p implies not-not-p
    not-not : P -> ((f : P -> ⊥) -> ⊥)
    not-not p = λf. f p
    
    -- not-p implies not-not-not-p
    not-not-not : (P -> ⊥) -> (((P -> ⊥) -> ⊥) -> ⊥)
    not-not-not np = λf. f np

    -- not-not-not-p implies not-p
    not-p : (((P -> ⊥) -> ⊥) -> ⊥) -> (P -> ⊥)
    not-p nnnp = λp. nnnp (not-not p)
Now it all just turns into function application :)