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Initialization in C++ is bonkers (2017)

https://blog.tartanllama.xyz/initialization-is-bonkers/
126•todsacerdoti•8h ago

Comments

gnabgib•7h ago
Small discussion at the time (42 points, 6 comments) https://news.ycombinator.com/item?id=14532478

Related: Initialization in C++ is Seriously Bonkers (166 points, 2019, 126 points) https://news.ycombinator.com/item?id=18832311

nlehuen•7h ago
Not to worry, there is a 278 page book about initialization in C++!

https://leanpub.com/cppinitbook

(I don't know whether it's good or not, I just find it fascinating that it exists)

nitrogen99•7h ago
Well, authors are incentivized into writing long books. Having said that it obviously doesn't take away the fact that C++ init is indeed bonkers.
harry8•5h ago
What would be the incentive for making this a long book? Couldn't be money.
Analemma_•5h ago
I imagine if I'd managed to actually memorize all of C++'s initialization rules, I'd probably have to write a book too just to get it all out, or I'd lose my sanity.
jcelerier•4h ago
It is actually. It's been shown that longer books make more sales as they are considered more trustworthy, so authors are incentivized to artificially drag them longer than they actually require
bhk•4h ago
Wow! Exhibit 1 for the prosecution.
kazinator•4h ago
C++ doesn't have initiation hazing rituals, but initialization hazing rituals. (One of which is that book.)
ts4z•7h ago
This is a specialization of the general statement that C++ is bonkers.
lblume•11m ago
Unlike Rust, C++ at least has specialization...
timewizard•6h ago
> Explicitly initialize your variables, and if you ever fall in to the trap of thinking C++ is a sane language, remember this

It's a systems language. Systems are not sane. They are dominated by nuance. In any case the language gives you a choice in what you pay for. It's nice to be able to allocate something like a copy or network buffer without having to pay for initialization that I don't need.

vacuity•6h ago
I think in this case it's not amiss to mention Rust. Rust gives a compile error if it's not certain a variable is initialized. Option is the standard dynamic representation of this, and works nicely in the context of all Rust code. MaybeUninint is the `unsafe` variant that is offered for performance-critical situations.
gosub100•6h ago
That may have made sense in the days of < 100 MHz CPUs but today I wish they would amend the standard to reduce UB by default and only add risky optimizations with specific flags, after the programmer has analyzed them for each file.
jcelerier•5h ago
> That may have made sense in the days of < 100 MHz CPUs

you don't know how much C++ code is being written for 100-200MHz CPUs everyday

https://github.com/search?q=esp8266+language%3AC%2B%2B&type=...

I have a codebase that is right now C++23 and soon I hope C++26 targeting from Teensy 3.2 (72 MHz) to ESP32 (240 MHz). Let me tell you, I'm fighting for microseconds every time I work with this.

vjvjvjvjghv•5h ago
I bet even there you have only a few spots where it really makes a difference. It’s good to have the option but I think the default behavior should be safer.
jcelerier•4h ago
I don't know, way too often often my perf traces are evenly distributed across a few hundred functions (at best), without any clear outlier.
gosub100•4h ago
"how much code" =/= how many developers.

the people who care about clock ticks should be the ones inconvenienced, not ordinary joes who are maintaining a FOSS package that is ultimately stuck by a 0-day. It still takes a swiss-cheese lineup to get there, for sure. but one of the holes in the cheese is C++'s default behavior, trying to optimize like it's 1994.

jcelerier•4h ago
> the people who care about clock ticks

I mean that's pretty much the main reason for using c++ isn't it? Video games, real-time media processing, CPU ai inference, network middleware, embedded, desktop apps where you don't want startup time to take more than a few milliseconds...

gosub100•4h ago
No, it's not a dichotomy of having uninitialized data and fast startup or wait several milliseconds for a jvm or interpreter to load a gigabyte of heap allocated crap.
PaulDavisThe1st•48m ago
it's not about startup time. it's about computational bandwidth and latency once running.
timewizard•5h ago
CPU speed is not memory bandwidth. Latency and contention always exist. Long lived processes are not always the norm.

In another era we would have just called this optimal. https://x.com/ID_AA_Carmack/status/1922100771392520710

wffurr•4h ago
>> Systems are not sane.

“The systems programmer has seen the terrors of the world and understood the intrinsic horror of existence.”

https://www.usenix.org/system/files/1311_05-08_mickens.pdf

creata•2h ago
C and Rust both tend to be more sane than C++, though, so you can't just pin it on C++ being a systems programming language.
vitaut•6h ago
https://www.reddit.com/r/ProgrammerHumor/comments/8nn4fw/for...
e-dant•6h ago
Let the language die, hope it goes quicker than cobol.
gosub100•6h ago
COBOL is alive and well. Why would a company rewrite a codebase that has decades of error free functionality? What do they get?
cheema33•5h ago
> Why would a company rewrite a codebase that has decades of error free functionality? What do they get?

All well and good if it is something you do not have to modify/maintain on a regular basis. But, if you do, then the ROI on replacing it might be high, depending on how much pain it is to keep maintaining it.

We have an old web app written in asp.net web forms. It mostly works. But we have to maintain it and add functionality to it. And that is where the pain is. We've been doing it for a few years but the amount of pain it is to work on it is quite high. So we are slowly replacing it. One page at a time.

gosub100•4h ago
the insurance companies running COBOL don't care. it's cheaper to pay a cowboy $X00,000/yr to keep the gravy dispenser running than trying to modify it. by definition, this is code that's been in use for decades. Why change it?
bdangubic•6h ago
“quicker than cobol” means it will die in the next 100 years (maybe) :)
jimbob45•4h ago
I suspect the committee agrees with you. I think they’ve anticipated a competitor coming to kill C++ for two decades now and see themselves as keeping C++ on life support for those who need it.

It’s shameful that there’s no good successor to C++ outside of C# and Java (and those really aren’t successors). Carbon was the closest we came and Google seems to have preemptively dropped it.

compiler-guy•4h ago
Carbon is still quite active.
jimbob45•2h ago
The addition of a safety design is a shift in our milestones for v0.1, and you can see the difference here. Both of these are fundamental parts of v0.1, and will take long enough that the earliest date for v0.1 is pushed out to the end of 2026

Look, no one is more excited than me for this, but this is reaching Star Citizen levels of delays.

wffurr•4h ago
The latest Carbon newsletter is here, from March: https://github.com/carbon-language/carbon-lang/discussions/5...
compiler-guy•4h ago
https://www.phoronix.com/news/GCC-15-Merges-COBOL

COBOL Language Frontend Merged For GCC 15 Compiler Written by Michael Larabel in GNU on 11 March 2025 at 06:22 AM EDT. 33 Comments

greesil•2h ago
I don't think it's going anywhere, too much existing code that's still useful. People STILL use Fortran 77 for goodness sake.
lblume•8m ago
Fortran may still be used but is considered functionally dead nonetheless. Nobody is hiring Fortran devs anymore (and those who do put themselves in a really hard market position). Yet, learning C++ might still be a more valuable skill than learning Rust.
trealira•2h ago
C++ is not going anywhere. It's even still used in gamedev to make new games. It's used in HPC and scientific computing. Windows applications often use it. And so on.
beached_whale•6h ago
And for the most part it does what you expect.
jandrewrogers•6h ago
I largely prefer modern C++ as systems languages go but there is no getting around the fact that the initialization story in C++ is a hot mess. Fortunately, it mostly does what you need it to even if you don't understand it.
vjvjvjvjghv•5h ago
And sometimes it doesn’t do what you think it does.
waynecochran•6h ago
This idea that everything must be initialized (i.e. no undefined or non-deterministic behavior) should never be forced upon a language like C++ which rightly assumes the programmer should have the final say. I don't want training wheels put on C++ -- I want C++ do exactly and only what the programmer specifies and no more. If the programmer wants to have uninitialized memory -- that is her business.
anon-3988•6h ago
If they want the program to do exactly what is told they won't get to have optimization.
waynecochran•1h ago
That's the whole point of UB -- it leaves open more possibilities for optimization. If everything is nailed down, then the options are more restricted.
GrantMoyer•5h ago
The problem is that the initialization semantics are so complex in C++ that almost no programmer is actually empowered to exercise their final say, and no programmer without significant effort.

And that's not just said out of unfamiliarity. I'm a professional C++ developer, and I often find I'm more familiar with C++'s more arcane semantics than many of my professional C++ developer co-workers.

vjvjvjvjghv•5h ago
The dev should have the option to turn it off but I think that removing a lot of undefined and non deterministic behavior would be a good thing. When I did C++ I initialized everything and when there was a bug it could usually be reproduced. There are a few cases where it makes sense performance wise to not initialize but those cases are very small compared to most other code where undefined behavior causes a ton of intermittent bugs.
yxhuvud•5h ago
The discussion about what should be the default behavior and of what should be the opt-in behavior is very different from what should be possible. It is definitely clear that in c++, it must be possible to not initialize variables.

Would it really be that unreasonable to have initialisation be opt-out instead of opt-in? You'd still have just as much control, but it would be harder to shoot yourself in the foot by mistake. Instead it would be slightly more easy to get programs that can be optimised.

frollogaston•5h ago
C++ is supposed to be an extension of C, so I wouldn't expect things to be initialized by default, even though personally I'm using C++ for things where it'd be nice.

I'm more annoyed that C++ has some way to default-zero-init but it's so confusing that you can accidentally do it wrong. There should be only one very clear way to do this, like you have to put "= 0" if you want an int member to init to 0. If you're still concerned about safety, enable warnings for uninitialized members.

tonyhart7•5h ago
"If the programmer wants to have uninitialized memory -- that is her business."

idk, seems like years of academic effort and research wasted if we do the way C++ do it

loeg•5h ago
As someone who has to work in C++ day in and day out: please, give me the fucking training wheels. I don't want UB if I declare an object `A a;` instead of `A a{};`. At least make it a compiler error I can enable!
ryandrake•5h ago
Ideally, there would be a keyword for it. So ‘A a;’ would not compile. You’d need to do ‘A a{};’ or something like ‘noinit A a;’ to tell the compiler you’re sure you know what you are doing!
waynecochran•1h ago
Not me. I want to give the optimizer the freedom to do its thing. If I say something does not need to be initialized, then the optimizer has one less constraint to worry about.
wiseowise•56m ago
We’ve already understood you don’t want sane language design, you don’t need to repeat it ten times.
charlotte-fyi•5h ago
The entire problem is that what the programmer wants to do and what the program actually does isn't always clear to the programmer.
kstrauser•5h ago
By that logic, you'd have to dislike the situations where C++ does already initialize variables to defined values, like `int i;`, because they're removing your control and forcing training wheels upon you.

So, do you?

jcelerier•4h ago

    int i;
does not initialize the value.
kstrauser•4h ago
It's a gotcha to be sure. Sometimes it does, sometimes it doesn't. From a reference[0]:

  #include <string>
  
  struct T1 { int mem; };
  
  struct T2
  {
      int mem;
      T2() {} // “mem” is not in the initializer list
  };
  
  int n; // static non-class, a two-phase initialization is done:
  // 1) zero-initialization initializes n to zero
  // 2) default-initialization does nothing, leaving n being zero
  
  int main()
  {
      [[maybe_unused]]
      int n;            // non-class, the value is indeterminate
      std::string s;    // class, calls default constructor, the value is ""
      std::string a[2]; // array, default-initializes the elements, the value is {"", ""}
      //  int& r;           // Error: a reference
      //  const int n;      // Error: a const non-class
      //  const T1 t1;      // Error: const class with implicit default constructor
      [[maybe_unused]]
      T1 t1;            // class, calls implicit default constructor
      const T2 t2;      // const class, calls the user-provided default constructor
      // t2.mem is default-initialized
  }
That `int n;` on the 11th line is initialized to 0 per standard. `int n;` on line 18, inside a function, is not. And `struct T1 { int mem; };` on line 3 will have `mem` initialized to 0 if `T1` is instantiated like `T1 t1{};`, but not if it's instantiated like `T1 t1;`. There's no way to tell from looking at `struct T1{...}` how the members will be initialized without knowing how they'll be called.

C++ is fun!

[0]https://en.cppreference.com/w/cpp/language/default_initializ...

90s_dev•4h ago
Stroustrup once said

> "There's a great language somewhere deep inside of C++"

or something to that effect.

portaltonowhere•4h ago
Unless `i` is global…
waynecochran•1h ago
Most cases, e.g. local var declaration. `int i` does not initialize i.
Maxatar•4h ago
It's so ironic hearing a comment like this. If what you really want is for C++ to do only what you strictly specified, then you'd always release your software with all optimizations disabled.

But I'm going to go out on a limb here and guess you don't do that. You actually do allow the C++ compiler to make assumptions that are not explicitly in your code, like reorder instructions, hoist invariants, eliminate redundant loads and stores, vectorize loops, inline functions, etc...

All of these things I listed are based on the compiler not doing strictly what you specified but rather reinterpreting the source code in service of speed... but when it comes to the compiler reinterpreting the source code in service of safety.... oh no... that's not allowed, those are training wheels that real programmers don't want...

Here's the deal... if you want uninitialized variables, then explicitly have a way to declare a variable to be uninitialized, like:

    int x = void;
This way for the very very rare cases where it makes a performance difference, you can explicitly specify that you want this behavior... and for the overwhelming majority of cases where it makes no performance impact, we get the safe and well specified behavior.
frollogaston•4h ago
How about int x = 0 if you want 0. Just `int x;` doesn't make it clear that you want 0.
kstrauser•4h ago
Safe defaults matter. If you're using x to index into a array, and it's randomly initialized as +-2,000,000,000 because that's what happened to be in that RAM location when the program launched, and you use it before explicitly setting it, you're gonna have a bad time.

And if you used it with a default value of 0, you're going to end up operating on the 0th item in the array. That's probably a bug and it may even be a crasher if the array has length 0 and you end up corrupting something important, but the odds of it being disastrous are much lower.

waynecochran•1h ago
The whole advantage of UB is that this places less restraints on what the optimizer can do. If I say something does not need to be initialized I am giving the optimizer the freedom to do more!
TheBicPen•31m ago
So what's the issue with introducing explicit syntax to do exactly that if you want to? A safe default does not preclude you from opting out of safety with a bit of syntax or perhaps a compiler flag.
90s_dev•4h ago
That's the inherent tension, though, isn't it?

A programmer wants the compiler to accept code that looks like a stupid mistake when he knows it's not.

But he also wants to have the compiler make sure he isn't making stupid mistakes by accident.

How can it do both? They're at odds.

wiseowise•53m ago
> How can it do both? They're at odds.

By doing what’s right.

https://en.wikipedia.org/wiki/Principle_of_least_astonishmen...

titzer•4h ago
> I want C++ do exactly and only what the programmer specifies and no more.

Most programmers aren't that good and you're mostly running other people's code. Bad defaults that lead to exploitable security bugs is...bad defaults. If you want something to be uninitialized because you know it then you should be forced to scream it at the compiler.

shadowdev1•6h ago
Heh, low comments on C++ posts now. A sign of the times. My two cents anyway.

I've been using C++ for a decade. Of all the warts, they all pale in comparison to the default initialization behavior. After seeing thousands of bugs, the worst have essentially been caused by cascading surprises from initialization UB from newbies. The easiest, simplest fix is simply to default initialize with a value. That's what everyone expects anyway. Use Python mentality here. Make UB initialization an EXPLICIT choice with a keyword. If you want garbage in your variable and you think that's okay for a tiny performance improvement, then you should have to say it with a keyword. Don't just leave it up to some tiny invisible visual detail no one looks at when they skim code (the missing parens). It really is that easy for the language designers. When thinking about backward compatibility... keep in mind that the old code was arguably already broken. There's not a good reason to keep letting it compile. Add a flag for --unsafe-initialization-i-cause-trouble if you really want to keep it.

C++, I still love you. We're still friends.

juliangmp•5h ago
> When thinking about backward compatibility... keep in mind that the old code was arguably already broken. There's not a good reason to keep letting it compile.

Oh how I wish the C++ committee and compiler authors would adopt this way of thinking... Sadly we're dealing with an ecosystem where you have to curate your compiler options and also use clang-tidy to avoid even the simplest mistakes :/

Like its insane to me how Wconversion is not the default behavior.

zahlman•2h ago
>Oh how I wish the C++ committee and compiler authors would adopt this way of thinking

Many different committees, organizations etc. could benefit, IMO.

motorest•1h ago
> Oh how I wish the C++ committee and compiler authors would adopt this way of thinking...

I disagree. If you expect anyone to adopt your new standard revision, the very least you need to do is ensure their code won't break just by flipping s flag. You're talking about production software, many of which has decades worth of commit history, which you simply cannot spend time going through each and every single line of code of your >1M LoC codebase. That's the difference between managing production-grade infrastructure and hobbyist projects.

loeg•5h ago
Compilers should add this as a non-standard extension, right? -ftrivial-auto-var-init=zero is a partial solution to a related problem, but it seems like they could just... not have UB here. It can't be that helpful for optimization.
Matheus28•5h ago
Yes but it’s not portable. If zero initialization were the default and you had to opt-in with [[uninitialized]] for each declaration it’d be a lot safer. Unfortunately I don’t think that will happen any time soon.
loeg•5h ago
I don't really care if it isn't portable. I only have to work with Clang, personally.

> If zero initialization were the default and you had to opt-in with [[uninitialized]] for each declaration it’d be a lot safer.

I support that, too. Just seems harder than getting a flag into Clang or GCC.

ryandrake•5h ago
Portability is always for the other guy’s sake, not your own. That’s why so many people don’t care about it.
loeg•3h ago
Again, I'm not opposed to the idea, it just seems more challenging logistically.
tialaramex•3h ago
You probably don't want zero initialization if you can help it.

Ideally, what you want is what Rust and many modern languages do: programs which don't explain what they wanted don't compile, so, when you forget to initialize that won't compile. A Rust programmer can write "Don't initialize this 1024 byte buffer" and get the same (absence of) code but it's a hell of a mouthful - so they won't do it by mistake.

The next best option, which is what C++ 26 will ship, is what they called "Erroneous Behaviour". Under EB it's defined as an error not to initialize something you use but it is also defined what happens so you can't have awful UB problems, typically it's something like the vendor specifies which bit pattern is written to an "unintialized" object and that's the pattern you will observe.

Why not zero? Unfortunately zero is too often a "magic" value in C and C++. It's the Unix root user, it's often an invalid or reserved state for things. So while zero may be faster in some cases, it's usually a bad choice and should be avoided.

motorest•2m ago
> Ideally, what you want is what Rust and many modern languages do: programs which don't explain what they wanted don't compile, so, when you forget to initialize that won't compile.

I think you're confusing things. You're arguing about static code analysis being able to identify uninitialized var reads. All C++ compilers already provide support for flags such as -Wuninitiaized.

leni536•28m ago
Something like that is heading into C++26 actually. Except the initialization is not to zero, but to some unspecified value (with explicit intention of not allowing leaking garbage) and allowing to trap. It's called "erroneous values".
MichaelRo•2h ago
>> Of all the warts, they all pale in comparison to the default initialization behavior.

Come on. That's nothing compared to the horrors that lay in manual memory management. Like I've never worked with a C++ based application that doesn't have crashes lurking all around, so bad that even a core dump leaves you clueless as to what's happening. Couple OOP involving hundreds of classes and 50 levels deep calls with 100s of threads and you're hating your life when trying to find the cause for yet another crash.

kaashif•2h ago
50 levels deep? With some of the template metaprogramming I've seen, looking at just the types for just one level will not only fill your screen, but take up megabytes on disk...
josefx•1h ago
> keep in mind that the old code was arguably already broken

The code is only broken if the data is used before anything is written to it. A lot of uninitialized data is wrapped by APIs that prevent reading before something was written to it, for example the capacity of a standard vector, buffers for IO should only access bytes that where already stored in them. I have also worked with a significant number of APIs that expect a large array of POD types and then tell you how many entries they filled.

> for a tiny performance improvement

Given how Linux allocates memory pages only if they are touched and many containers intentionally grow faster then they are used? It reduces the amount of page faults and memory use significantly if only the used objects get touched at all.

riehwvfbk•1h ago
You are very very unlikely to trigger Linux overcommit behavior by not initializing a member variable. It's even more unlikely for this to be a good thing.

In effect, you are assuming that your uninitialized and initialized variables straddle a page boundary. This is obviously not going to be a common occurrence. In the common case you are allocating something on the heap. That heap chunk descriptor before your block has to be written, triggering a page fault.

Besides: taking a page fault, entering the kernel, modifying the page table page (possibly merging some VMAs in the process) and exiting back to userspace is going to be A LOT slower than writing that variable.

OK you say, but what if I have a giant array of these things that spans many pages. In that case your performance and memory usage are going to be highly unpredictable (after all, initializing a single thing in a page would materialize that whole page).

OK, but vectors. They double in size, right? Well, the default allocator for vectors will actually zero-initialize the new elements. You could write a non-initializing allocator and use it for your vectors - and this is in line with "you have to say it explicitly to get dangerous behavior".

motorest•13m ago
> You are very very unlikely to trigger Linux overcommit behavior by not initializing a member variable.

The problem with your assumption is that you're just arguing that it's ok for code to be needlessly buggy if you believe the odds this bug is triggered are low. OP points out a known failure mode and explains how a feature eliminates it. You intentionally ignore it for no reason.

This assumption is baffling when, in the exact same thread, you see people whining about C++ for allowing memory-related bugs to exist.

josefx•10m ago
> In effect, you are assuming that your uninitialized and initialized variables straddle a page boundary

You are assuming that I am working with small data structures, don't use arrays of data, don't have large amounts of POD members, ... .

> That heap chunk descriptor before your block has to be written, triggering a page fault.

So you allocate one out of hundreds of pages? The cost is significantly less than the alternative.

> In that case your performance and memory usage are going to be highly unpredictable (after all, initializing a single thing in a page would materialize that whole page).

As opposed to initializing thousands of pages you will never use at once? Or allocating single pages when they are needed?

> Well, the default allocator for vectors will actually zero-initialize the new elements.

I reliably get garbage data after the first reserve/shrink_to_fit calls. Not sure why the first one returns all zero, I wouldn't rely on it.

markhahn•5h ago
Most of that actually just makes sense if you approach it from the historic,low-level, minimalist direction. But maybe if you're coming from some other, higher-comfort language...
frollogaston•4h ago
Coming from C, none of this made sense to me. Wut is `foo() = default;`? If you want a default value of 0, why isn't it just

  struct foo {
    int a = 0;
  };
In Python, which is higher-level ofc, I still have to do `foo = 0`, nice and clear.
zabzonk•4h ago
> If you want a default value of 0, why isn't it ...

It is.

Maxatar•3h ago
`foo() = default;` is an explicit way to generate a default constructor for `foo`. The default constructor works by recursively calling the default constructors for all class instance fields. In C++ there are a bunch of rules about when a class has a default constructor or not, but by explicitly declaring one you are guaranteed to have it so long as all your class instance fields have default constructors.

Your example of having a field called `a` that is initialized to 0 is perfectly valid C++ as well but it's not the same as an explicitly declared default constructor.

motorest•43m ago
> Coming from C, none of this made sense to me. Wut is `foo() = default;`?

C does not have member functions, let alone special member functions such as constructors. It's understandable that someone with a C background who never had any experience using a language besides C would struggle with this sort of info.

C++ improved upon C's developer experience by introducing the concept of special member functions. These are functions which the compiler conveniently generates for you when you write a simple class. This covers constructors (copy constructors and move constructors too). This is extremely convenient and eliminates the need for a ton of boilerplate code.

C++ is also smart enough to know when not to write something it might surprise you. Thus, if you add anything to a basic class that would violate assumptions on how to generate default implementations for any of these special member functions, C++ simply backs off and doesn't define them.

Now, just because you prevented C++ from automatically defining your constructors, that does not mean you don't want them without having to add your boilerplate code. Thus, C++ allows developers to define these special member functions using default implementations. That's what the default keyword is used for.

Now, to me this sort of complaining just sounds like nitpicking. The whole purpose of special member functions and default implementations is to help developers avoid writing boilerplate code to have basic implementations of member functions you probably need anyway. For basic, predictable cases, C++ steps in and helps you out. If you prevent C++ from stepping in, it won't. Is this hard to understand?

More baffling, you do not have to deal with these scenarios if you just declare and define the special member functions you actually want. This was exactly how this feature was designed to work. Is this too hard to follow or understand?

I think the problem with C++ is that some people who are clearly talking out of ignorance feel the need to fabricate arguments about problems you will experience if you a) don't know what you are doing at all and aren't even interested in learning, b) you want to go way out of your way to nitpick about a tool you don't even use. Here we are, complaining about a keyword. If we go through the comments, most of the people doing the bulk of the whining don't even know what it means or how it's used. They seem to be invested in complaining about things they never learned about. Wild.

nyarlathotep_•5h ago
Aside, but the author of this blog is the author of https://nostarch.com/building-a-debugger

A wonderful exploration of an underexplored topic--I've pre-ordered the hard copy and have been following along with the e-book in the interim.

jeffbee•5h ago
It's fun to cross the streams of HN catnip.

C++ sucks, it's too hard to use, the compiler should generate stores all over the place to preemptively initialize everything!

Software is too bloated, if we optimized more we could use old hardware!

Maxatar•4h ago
I'm not familiar with programming languages that generate redundant stores in order to initialize anything.

Usually what happens is the language requires you to initialize the variable before it's read for the first time, but this doesn't have to be at the point of declaration. Like in Java you can declare a variable, do other stuff, and then initialize it later... so long as you initialize it before reading from it.

Note that in C++, reading from a variable before writing to it is undefined behavior, so it's not particularly clear what benefit you're getting from this.

zahlman•2h ago
> Note that in C++, reading from a variable before writing to it is undefined behavior, so it's not particularly clear what benefit you're getting from this.

You gain the benefit that the compiler can assume the code path in question is impossible to reach, even if there's an obvious way to reach it. To my understanding, this can theoretically back-propagate all the way to `main()` and make the entire program a no-op.

josefx•49m ago
> Note that in C++, reading from a variable before writing to it is undefined behavior, so it's not particularly clear what benefit you're getting from this.

The compiler cannot always tell if a variable will be written to before it is accessed. if you have a 100kb network buffer and you call int read = opaque_read(buffer); the compiler cannot tell how much or if anything at all was written to buffer and how size relates to it, it would be forced to initialize every byte in it to zero. A programmer can read the API docs, see that only the first read bytes are valid and use the buffer without ever touching anything uninitialized. Now add in that you can pass mutable pointers and references to nearly anything in C++ and the compiler has a much harder time to tell if it has to initialize arguments passed to functions or if the function is doing the initialization for it.

kazinator•4h ago
> This rule makes sense when you think about it

No, it is bonkers; stick to your consistent point, please.

These two should have exactly the same effect:

  bar() = default;       // inside class declaration

  bar::bar() = default;  // outside class declaration
The only difference between them should be analogous to the difference between an inline and non-inline function.

For instance, it might be that the latter one is slower than the former, because the compiler doesn't know from the class declaration that the default constructor is actually not user-defined but default. How it would work is that a non-inline definition is emitted, which dutifully performs the initialization, and that definition is actually called.

That's what non-bonkers might look like, in any case.

I.e. both examples are rewritten by the compiler into

  bar() { __default_init; }

  bar::bar() { __default_init; }
where __default_init is a fictitious place holder for the implementation's code generation strategy for doing that default initialization. It would behave the same way, other than being inlined in the one case and not in the other.

Another way that it could be non-bonkers is if default were simply not allowed outside of the class declaration.

  bar::bar() default;  // error, too late; class declared already!
Something that has no hope of working right and is easily detectable by syntax alone should be diagnosed. If default only works right when it is present at class declaration time, then ban it elsewhere.
alexvitkov•3h ago
This is not even worth thinking about, just type " = {}" on every struct/class member and every variable declaration, and forget about all this nonsense.
dataflow•3h ago
That's a bad idea. It defeats tools (warnings, sanitizers, etc.) that try to tell you you have forgotten to place the semantically correct value in your variables.

If you want indiscriminate initialization, a compiler flag is the way, not forcing it in the source code.

adityamwagh•3h ago
Just gonna leave this here :)

https://youtu.be/7DTlWPgX6zs?si=-jNEIYQf1_uUioD-

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